zqrx.net
ǰλãҳ >> 1ʮ2ʮ3ʮ4ʮ5ʮ6365ڶ >>

1ʮ2ʮ3ʮ4ʮ5ʮ6365ڶ

66795(1+365=366 365/2=182 ʣһ183 :366*182+183 =66795)

1ʮ2ʮ3ʮ4ʮ5ʮ6һֱӵ100ڼ?:1+2+3+4++97+98+99+100=(1+100)+(2+99)+(3+98)++(50+51) =(1+100)*50 =101*50 =5050:1ʮ2ʮ3ʮ4ʮ5ʮ6һֱӵ1005050.

=(1+36)*18=37*18=666,ѽ,,Ͻǡɴ𰸡,֧һ.

5050

1ʮ2ʮ3ʮ4ʮ5ʮ6㷨=(1+6)+(2+5)+(3+4)=7+7+7=21

1ʮ2ʮ3ʮ4ʮ5ʮ6++23=(1+23)+(2+22)+(3+21)++(11+13)+12=24*11+12=276

=401*400/2=80200

1+2ʮ3ʮ4ʮʮ20172035153

50*(50+1)/2=1275

1+20=2+19=3+18==10+11, 10. 1ʮ2ʮ3ʮ4ʮ5ʮ6ʮ7ʮ8ʮ9ʮʮ20=(1+20)+(2+19)++(10+11) =21*10 =210

վҳ | վͼ
All rights reserved Powered by www.zqrx.net
copyright ©right 2010-2021
磬ַϵͷzhit325@qq.com